Solution:
Temperature of neutron T = 27+273=300K
De-Broglie wavelength in this case is given by
Where, h = Plank constant = 6.626x10-34Js ,
m= mass of neutron = 1.67x10-27Kg
K = Boltzmann constant = 1.38x10-23J/ kelvin
Ans: λ = 1.45 A0
Tags
quantummechanics