Given-:
Ca(HCO3)2 =
8.1mg ; Mg(HCO3)2 = 7.5 mg ; CaSO4 = 13.6 mg ; MgSO4 = 12mg ; MgCL2
= 2 mg.
Solution -:
Calculation of CaCO3 equivalents:
Constituent |
Amount |
Multiplication factor |
CaCO3 Equivalents |
Need |
|
A(mg/L) |
M |
A*M(mg/L) |
Lime = L Soda = S |
Ca(HCO3)2 |
8.1 |
100/162 |
8.1*100/162 = 5 |
L |
Mg(HCO3)2 |
7.5 |
100/146 |
7.5*100/146 = 5.14 |
2L |
CaSO4 |
13.6 |
100/136 |
13.6*100/136 = 10 |
S |
MgSO4 |
12 |
100/120 |
12*100/120 = 10 |
L+S |
MgCL2 |
2 |
100/95 |
2*100/95 =
2.1 |
L-S |
Lime requirement ={74/100[ Ca(HCO3)2 +2Mg(HCO3)2 + MgSO4 + MgCL2 ]*volume/106 } kg
= { 74/100 [5+2*5.14+10+2.1]* 5*104 /106 }kg
=1.013kg
Soda requirement = {106/100[CaSO4 + MgSO4 + MgCL2 ]*volume/106 } kg
={106/100[10+10+2.1]* 5*104 /106 }kg
=1.17kg
Tags
waterchemistry